number density of electrons in a wire is 8.5 X10^28 m^3. what is time taken by an electron to drift from one end of wire 2.2m long to other end. If area of cross section of wire is 2.0 X 10^-6 m^2 & is carrying a current of 6.0 A
Time = distance / velocity = d*[nqA /I
Where d is the length of the wire, n is number density of electronsthe number denisty q is the charge of electron , A is the area of cross section , and I is the current
Time = 2.2*8.5e28* 1.602e-19 * 2.0e-6/ 6 = *nqA /I = 9985.8 s
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Nice cleanup, Pearl. Don't you owe me an acknowledgment?
Charge denumber density of electronsnsity Qd (C/m^3) = charge carrier density (e/m^3)*1.60218E-19 (C/e)
= 1.36185E10 C/m^3
v = I/(Qd*area) = 2.2028858E-4 m/s
t = L/v = 9986.9 s
Pearlsawme's equations account for length and area twice. (S)he should just divide nq by I to get t.
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